Breaking Even

Alice and Bob each start with $4 and bet on a series of 8 successive coin tosses. For each toss, if the coin lands on heads, Alice gives Bob $1; if it lands on tails, Bob gives Alice $1. What is the probability that they break even after the 8 rounds, with neither of them ever running out of money?

Answer

To break even after 8 tosses, there must be exactly 4 heads and 4 tails. The number of ways to achieve this is:

\[ \binom{8}{4} = 70. \]

However, we must exclude the two outcomes that lead to bankruptcy:

\[ \text{HHHHTTTT and TTTTHHHH}. \]

Thus, the number of favorable outcomes is:

\[ 70 - 2 = 68. \]

The total number of possible outcomes when flipping a coin 8 times is:

\[ 2^8 = 256. \]

Therefore, the probability of breaking even without bankruptcy is:

\[ \frac{68}{256} = \frac{17}{64}. \]
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