Long Maturity
Consider an at-the-money call option on a stock with an initial price of $190 and maturity \(T=1000\) years. Determine its price at \(t=0\) under Black–Scholes.
Answer
We start from the BS formula for a non-dividend stock:
\[
C = S\,N(d_1)\;-\;K\,e^{-rT}N(d_2).
\]
As \(T\to\infty\) the second term \(K\,e^{-rT}N(d_2)\to0\), so
\[
C \approx S\,N(d_1).
\]
i.e. approximate to the stock itself times the \(\Delta\) of the option.
Now, at very short maturities an ATM call’s delta \(N(d_1)\) behaves like a digital (jumping between 0 and 1), but as \(T\) grows the \(\Delta\)–\(S\) curve "flattens" and the ATM delta rises toward 1 (see the questions above for this). Hence,
\[
C\approx S = \$190.
\]
Notes and comments
Comment 1: By the same logic, an ATM put would have \(\;P = K\,e^{-rT}N(-d_2) - S\,N(-d_1)\approx0 - 0=0,\) so essentially worthless.